Question

Show that the points (12,8),(-2,6),(6,0) are the verticises pf right-angled triangle and also show that the mid point of the hypotenuse is equidistant from the angular point

Answer 1

Let A = (12,8)
B = (-2,6)
C = (6,0)
Now apply distance formula and find the distances of AB, BC, CA.

then Apply Pythagoras theorem to prove that AB² = BC² + CA²

Then find the midpoint of AB (hypotenuse) by applying midpoint formula.
After that you will get points as P(5,7).

then last step just find the distance of P from C by distance formula.

Then to prove that the mid point of the hypotenuse is equidistant from the angular point, just divide the hypotenuse by 2 and then conclude.

Plzz do not remove my answer but instead i gave an idea of how to do the problem, if you do it yourself then you'll understand and will be able to do any similar problems to that.

Cheers and Plzz mark it as brainliest!!