Question

Show that the points (2,0) (-2,0) (0,2 ) are the vertices of a triangle also state with reason the type of triangle

Answer 1

Let point A = ( 2,0 ), B = ( - 2, 0 ) and C = ( 0,2 ).

Distance between AB =

$\sqrt{{(-2\:-\:2)}^{2}\:+\:{(0\:-\:0)}^{2}}$

AB =$\sqrt{16}$

AB = 4 units

Distance between BC =

$\sqrt{{(0\:+\:2)}^{2}\:+\:{(2\:-\:0)}^{2}}$

BC =$\sqrt{4\:+\:4}$

BC = $\sqrt{8}$

BC = 2$\sqrt{2}$ units.

Distance between AC =

$\sqrt{{(0\:-\:2)}^{2}\:+\:{(2\:-\:0)}^{2}}$

AC = $\sqrt{4\: + \:4}$

AC =$\sqrt{8}$

AC = 2$\sqrt{2}$ units.

Since, BC = AC = 2$\sqrt{2}$ units.

Two sides are equal. So, it is an $\tt{Isosceles \:triangle}$ .

Answer 2

hey mate

here is your answer