show that the points (2,0) ,(-2,0) and (0,2) are the vertices of a triangle. Also state with reason the type of the triangle.
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Step-by-step explanation:
Let point A = ( 2,0 ), B = ( - 2, 0 ) and C = ( 0,2 ).
Distance between AB = √[(-2-2)²+(0-0)²]
AB = √16
AB = 4 units
Distance between BC = √[(0+2)²+(2-0)²]
BC =√(4+4)
BC = √8
BC = 2√2
Distance between AC = √[(0-2)²+(2-0)²]
AC = √(4+4)
AC = √8
AC = 2√2
Since, BC = AC = 2√2
Two sides are equal, Therefore it is an Isosceles triangle
msp53:
Is it isosceles right angled triangle
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