show that the points (-2,1) (2,-2) and (5,2) are the vertices of triangle
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Step-by-step explanation:
Let A(2, -2), B(-2, 1) and C(5, 2) be the given points
⇒ AB=√(16-9)
⇒ AB=√(25)
Since, AB2+AC2=BC2
Therefore, ABC is a right angled triangle.
Length of the hypotenuse BC=√(50)=5√2
Area of ΔABC=(1/2)xABxAC
=(1/2)x√25x√25
=25/2 sq. units.
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