Show that the points (-2,3),(8,3) and (6,7) are the vertices of a right angle triangle
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Answered by
169
let the points be A, B and C respectively..
by distance formula
AB=√[(8+2)²+(3-3)²]
=10 units
similarly,
BC= 2√5 units
AC= 4√5 units
AC²+BC²= 20+80
=100
and AB²=100
therefore A, B, C form a right angled triangle
forming a right angle at C
(inverse of Pythagoras theorem)
by distance formula
AB=√[(8+2)²+(3-3)²]
=10 units
similarly,
BC= 2√5 units
AC= 4√5 units
AC²+BC²= 20+80
=100
and AB²=100
therefore A, B, C form a right angled triangle
forming a right angle at C
(inverse of Pythagoras theorem)
Answered by
39
Step-by-step explanation:
find the distance bet AB ,BC ,CA
and then
AC²+BC²= AB²
so ,20+80=100
it forms right angle at c ( by inverse of Pythagoras theorem) see in the above photo or pic and know the answer
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