Show that the points ( 3, -2), ( 1, 4) and ( -1, 10) are collinear.
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Let A( 3, -2 ), B( 1, 4 ), C( -1, 10 ).
Using distance formula,
AB = √{(3-1)² + (-2-4)²}
= √{4+36}
= √40
= 2√10
similarly,
BC = √{4+36}
= 2√10
AC = √{16+144}
= √160
= 4√10
AC = AB+BC
If 3 points are collinear, the on finding the distances between them, the largest distance should be sum of other 3 distances.
So, here A, B, C are collinear.
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Answered by
1
Your solution is in above pic.
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