Question

show that the points (3,-2), (-2,8) and (0,11) are collinear .

Answer 1

three points are collinear when ab=bc
here let a be (3,-2)
b (-2, 8)
c(0, 11)
now apply distance formula to find ab and bc they must be equal and if not then plzz tell me
hope it will help.u

Answer 2

Answer:

The points are A(3,-2), B(-2,8) and C(0,11) are not collinear .

Step-by-step explanation:

The given points are A(3,-2), B(-2,8) and C(0,11).

These points are collinear if slope of AB and BC are same.

Formula for slope:

$m=\frac{y_2-y_1}{x_2-x_1}$

Slope of AB is

$m_{AB}=\frac{8-(-2)}{-2-3}=-2$

Slope of BC is

$m_{BC}=\frac{11-8}{0-(-2)}=\frac{3}{2}$

Slope of AB and BC are not same, therefore the points are A(3,-2), B(-2,8) and C(0,11) are not collinear .