Question

show that the points (4, 2,), (7, 5) and (9, 7) do not form a triangle​

Answer 1

Answer:

Step-by-step explanation:

Let A(4, 2), B(7,5) and C(9,7) be the given points.........

By using Distance formula,

AB = √[(7-4)2 + (5-2)2]

=> √[(3)2 + (3)2]

=> √(9 + 9)

=>√18

=> 3√2 ...........

BC = √[(9-7)2 + (7-5)2]

=> √[(2)2 + (2)2]

=> √(4 + 4)

=> √8

=> 2√2 .........

AC = √[(9-4)2 + (7-2)2]

=> √[(5)2 + (5)2]

=> √(25 + 25)

=> √50

=> 5√2 .......

3√2 + 2√2 = 5√2

AB + BC = AC.

If any three points form a triangle, the sum of any two sides must be greater than the third side....

But here they are collinear points.......

So, they dont form a triangle.

Hence, proved!

Answer 2

Answer:

hi all friends

Step-by-step explanation:

it could help you may be