show that the points (5, -1 , 1) (7, -4, 7) (1, -6, 10) and (-1, -3, 4) are the vertices of a rhombus
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Let the points be P, Q, R,S
PQ= √(7-5)^2+(-4+1)^2 +(7-1)^2 = √4 +9 +36 = √49 = 7
Similarly calculate QR, RS and SP all will be 7
Also calculate diagonals PR and QS they will be different. Therefore P,Q,R,S are vertices of a rhombus.
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