Question

Show that the points (5,5), (6,4), (-2, 4) and (7,1) are concyclic, i.e., all
lie on the same circle. Find the equation, centre and radius of this circle.
.​

Answer 1

Answer:

Step-by-step explanation:

we can name the points as : A(5,5)  B(6,4)  C(-2,4) D(7,1)

so i think to proof this we have to proof that the vectors AB and CD can't be equal or in a relation in terms of each other , in anouther sense

Vector AB≠αDC  -----> (α ∈ R)

so let's calculate the coordinates of the vectors

AB(6-5 , 4-5)  which equals to AB(1,-1)

DC(7-(-2 , 1-5) which equals to DC(9,-4)

AB≠αDC

1=9α & -1=-4α' -----> if α≠α' so AB≠αDC which means the points are concyclic

i think it's the correct answer

Answer 2

Answer:

we can name the points as : A(5,5)  B(6,4)  C(-2,4) D(7,1)

so i think to proof this we have to proof that the vectors AB and CD can't be equal or in a relation in terms of each other , in anouther sense

Vector AB≠αDC  -----> (α ∈ R)

so let's calculate the coordinates of the vectors

AB(6-5 , 4-5)  which equals to AB(1,-1)

DC(7-(-2 , 1-5) which equals to DC(9,-4)

AB≠αDC

1=9α & -1=-4α' -----> if α≠α' so AB≠αDC which means the points are concyclic

Read more on Brainly.in - https://brainly.in/question/10265406#readmore

Step-by-step explanation: