Show that the points (5,5), (6,4), (-2, 4) and (7,1) are concyclic, i.e., all
lie on the same circle. Find the equation, centre and radius of this circle.
.
Answers
Answer:
Step-by-step explanation:
we can name the points as : A(5,5) B(6,4) C(-2,4) D(7,1)
so i think to proof this we have to proof that the vectors AB and CD can't be equal or in a relation in terms of each other , in anouther sense
Vector AB≠αDC -----> (α ∈ R)
so let's calculate the coordinates of the vectors
AB(6-5 , 4-5) which equals to AB(1,-1)
DC(7-(-2 , 1-5) which equals to DC(9,-4)
AB≠αDC
1=9α & -1=-4α' -----> if α≠α' so AB≠αDC which means the points are concyclic
i think it's the correct answer
Answer:
we can name the points as : A(5,5) B(6,4) C(-2,4) D(7,1)
so i think to proof this we have to proof that the vectors AB and CD can't be equal or in a relation in terms of each other , in anouther sense
Vector AB≠αDC -----> (α ∈ R)
so let's calculate the coordinates of the vectors
AB(6-5 , 4-5) which equals to AB(1,-1)
DC(7-(-2 , 1-5) which equals to DC(9,-4)
AB≠αDC
1=9α & -1=-4α' -----> if α≠α' so AB≠αDC which means the points are concyclic
Read more on Brainly.in - https://brainly.in/question/10265406#readmore
Step-by-step explanation: