show that the points (7,9),(3,-7),(4,6)are vertics of a right angled triangle
plz do it step by step
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A(7,8) B(3,-7) C(4,6)
AB=√((x2-x1)^2+(y2-y1)^2)
AB=√((3-7)^2+(-7-9)^2)
AB=√((-4)^2+(-16)^2)
AB=√(16+256)
AB=√272
BC=√((4-3)^2+(4+7)^2)
BC=√((1)^2+(11)^2)
BC=√(1+121)
BC=√122
AC=√((4-7)^2+(6-8)^2)
AC=√((-3)^2+(-2)^2)
AC=√(9+4)
AC=√13
Using Pythagoras therom
AC=√(AB^2+BC^2)
√13=√((√272)^2+(√122)^2)
√13=√(272+122)
√13=√394
therefore lhs is not equal to rhs
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