show that the points( 7 and 3) and (-2 ,5) and (3, - 4 )are vertices of an isosceles right triangle.
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Answer:
let A = 7,3
B=-2,5
C =3,-4
AB^2 = (7+2)^2 + (3-5)^2= 81+ 4=85
BC^2 = (-2-3)^2 +(5+4)^2 = 25 + 81= 106
CA^2 = (3-7)^2 +(-4-3)^2
=16 +49 =65
question is wrong
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