Question

show that the points A(1,1) , B(2,3), C(3,4) D (2,2) form parallelogram ABCD​

Answer 1

mid point of diagonal ad=(1/2,1/2)

mid point of diagonal BC=(1/2,1/2)

so both mid point intersect each other so the given ABCD is parallelogram

Answer 2

As we know diagonals of parallelogram bisect each other

let's prove

A( 1,1) C( 3,4)

x= 1+3)/2 = 4/2 = 2

y= (1+4)/2 = 5/2

Mid point of BD

B ( 2,3) D( 2,2)

X= 2+2)/2 = 4/2 = 2

Y= 3+2)/2 = 5/2

So It's a parallelogram

As mid point of AC = mid point of BD