Question

show that the points a(1,2),b(-1,-16)and c(0-1)line on the graph of the linear equation y=9x-7​

Answer 1

Step-by-step explanation:

You just need to plug these values in your linear equations

a(1,2)

2 = 9(1) - 7

2 = 2

b(-1 , -16)

-16 = 9(-1) - 7

-16 = -16

c(0,-1)

-1 = 9(0) - 7

-1 # - 7

i think third point is wrong as it doesn't satisfies the given equation

Answer 2

Answer:

Step-by-step explanation:

To show that the points lie on the graph of linear equation y=9x-7

We have to check for the given values

For 1st value/ordered pair ,

A(1,2) x = 1, y = 2

Substituting in the given eqn,

2=9(1)-7

=> 2=2

This ordered pair is satisfied

Second pair , B(-1,-16) x = -1,y=-16

=> -16 = 9(-1)-7

=> -16= -16

This pair also satisfies the eqn

Third pair , C(0,-7) x=0,y=-7

=> -7= 9(0)-7

=> -7 = -7

This one also satisfies the equation

So , all of the Values/pairs satisfies and are solutions of y=9x-7.

Hence they lie on the graph of linear equation y=9x-7