show that the points A(1, 2), B(-1, -16) and C(0, -7) lie on the graph of the linear equation y=9x-7
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Answer:
Step-by-step explanation:
Point A (1,2)
2 = 9 x 1 -7
2 = 9-7
2 = 2
Point B (-1,-16)
-16 = 9(-1) -7
-16 = -9 -7
-16 = -16
Point C (0,-7)
-7 = 9(0) -7
-7 = -7
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