Show that the points A(1,2) ,B(4,3), C(1,0) and D(-2,-1) are the vertices of a parallelogram.
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Given points are
A(−2,−1),B(1,0),C(4,3) and D(1,2)
A quadrilateral is a parallelogram if the opposite sides are equal.
∴AB^2 =(−2−1)^2 + (−1−0)^2
=9+1=10
BC^2 =(4−1)^2 + (3−0)^2
=9+9=18
CD^2 =(1−4)^2 + (2−3)^2
9+1=10
AD^2 =(−2−1)^2 + (−1−2)^2
=9+9=18
∴ The opposite sides of the quadrilateral ABCD are equal, the four points from a parallelogram.
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