Question

show that the points A (1,2) B (5,4) C (3,8) & D (-1,6) are vertices of a square​

Answer 1

Step-by-step explanation:

AB = √((5-1)^2 + (4-2)^2) = √20

BC = √((3-5)^2 + (8-4)^2) = √20

CD = √((-1-3)^2 + (6-8)^2) = √20

AD = √((-1-1)^2 + (6-2)^2) = √20

since AB=BC=CD=AD ,

ABCD is a square