show that the points A(6,4), B(5,2) and C(7,2) are the verticales of an isosceles triangle
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ANSWER
AB=
(6−5)
2
+(4+2)
2
=
37
AC=
(6−7)
2
+(4+2)
2
=
37
AB=AC
So, △ABC is isosceles.
Let D be the mid-point of BC. Then, coordinates of D are (
2
5+7
,
2
−2−2
) i.e., (6,−2).
Therefore,
AD=
(6−6)
2
+(4+2)
2
=
36
=6
Step-by-step explanation:
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