Question

show that the points A ( 7, 10 ) B (-2 , 5) C (3,4 ) are the vertices of the Right angled Triangle​

Answer 1

Answer:

AB = sq.root (-2-7)2+(5-10)2

sq.root (81+25)

sq.root 106

BC = sq.root (3+2)2+(4-5)2

sq.root (25+1)

sq.root 26

CA = sq.root (7-3)2+(10-4)2

sq.root(16+36)

sq.root 52

106+26= 52

132 is not equal to 52.