show that the points A(7,10),B(-2,5),c(3,-4) are the vertices of an isosceles right angle triangle.
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The given points are A (7, 10), B(-2, 5) and C(3, -4). and `(AC)^2 = (sqrt(212))^2 = 212. This show that ΔABC is right- angled at B. Therefore, the pointsA (7, 10), B(-2, 5) and C(3, -4).
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