Question

Show that the points A (8, 2), B (5, -3), C (0, 0) are vertices of

an Isosceles Triangle.​

Answer 1

Step-by-step explanation:

⋆HeyMate...!!

QUESTION:

Show that the triangle whose vertices are (8,−4),(9,5)(8,−4),(9,5) and (0,4)(0,4) is an isosceles triangle.

Solution:

We know that the distance between the two points (x1,y1)(x1,y1) and (x2,y2)(x2,y2) is 

d=√(x2−x1)2+(y2−y1)2d=(x2−x1)2+(y2−y1)2 

Let the given vertices be A=(8,−4)A=(8,−4), B=(9,5)B=(9,5) and C=(0,4)C=(0,4)

We first find the distance between A=(8,−4)A=(8,−4) and B=(9,5)B=(9,5) as follows:

AB=√(x2−x1)2+(y2−y1)2=√(10−2)2+(1−1)2=√82+02=√64=8AB=(x2−x1)2+(y2−y1)2=(10−2)2+(1−1)2=82+02=64=8

Similarly, the distance between B=(9,5)B=(9,5) and C=(0,4)C=(0,4) is:

BC=√(x2−x1)

hope it helps uh✌

Answer 2

Answer:

we use distance formula

Step-by-step explanation:

we know that in an isosceles triangle two side are equal so that their distance must be equal

now In triangle ABC ,

we need to prove that AC2+=AB2+BC2

SO that ABC is a right aagle triangle

AB=BC( ABC are the triangle )

Put the value of AB AND BC both the value are same

now , AB+BC=AC

Also AB2+BC2=AC2 ( BY PYTHAGORES THEORM )

Hence , prove that ABC is a right angled triangle .