Question

Show that the points A(8, 3), B(0, 9) and C(14, 11) are the vertices of an isosceles right

angled triangle.​

Answer 1

Answer:

first find AB

AB=√(0-8)^2 +(9-3)^2,

=√(-8)^2 +(6)^2

=√64+36

=√100

AB=10.

BC=√(14-0)^2 +(11-9)^2

=√(14)^2 + (2)^2

=√196+4

= √200

CA=√(8-14)^2 + (3-11)^2

= √(-6)^2 + (-8)^2

=√36+64

=√100

=10

two sides of a triangle are equally so they are the vertices of an isosceles triangle.

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