show that the points A(a,0), C(0, a√3) formvan equilateral triangle
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Given A(a,0) B(−a,0) C(0,a3)
AB=(a−(−a))2+(0−0)2=4a2=2a
BC=(0−(−a))2+(a3)2=4a2=2a
CA=(0−(−a))2+(a3)2=4a2=2a
∴ AB= BC = CA
Hence it is an equilateral triangle
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