Show that the points (a. a). (-a, -a) and (-root 3a, root 3a) are the vertices of an equilateral triangle.
SUPER URGENT PLS!!!!
Answers
Answered by
767
A = (a,a)
B = (-a,-a)
C = (-√3a,√3a)
AB=√(-a-a)²+(-a-a)²
√4a²+4a²
√8a²
2√2 a
BC=√(-√3a+a)²+(√3a+a)
√(1-√3)²a²+(√3+1)²a²
a√[ 1+3-2√3+3+1+2√3]
a[ √8]
2√2a
CA = √(-√3a-a)²+(√3a-a)²
√(-√3-1)²a²+(√3-1)²a²
a√[3+1+2√3+3+1-2√3]
a√8
2√2a
∴AB = BC = CA
it forms a eqilateral traingle
B = (-a,-a)
C = (-√3a,√3a)
AB=√(-a-a)²+(-a-a)²
√4a²+4a²
√8a²
2√2 a
BC=√(-√3a+a)²+(√3a+a)
√(1-√3)²a²+(√3+1)²a²
a√[ 1+3-2√3+3+1+2√3]
a[ √8]
2√2a
CA = √(-√3a-a)²+(√3a-a)²
√(-√3-1)²a²+(√3-1)²a²
a√[3+1+2√3+3+1-2√3]
a√8
2√2a
∴AB = BC = CA
it forms a eqilateral traingle
Answered by
168
Answer:
Step-by-step explanation:
Attachments:
Similar questions