Question

Show that the points from
A- (2.5,3.5) B(10,-4)C( 2.5,-2.5) and (-5,5) taken in order form the vertices of a parallelogram.​

Answer 1

Answer:

Slope of AD(m1)

5-3.5 1.5 = X2-X -5-2.5 -7.5

A (2.5,3.5) 0.1x10 -1

D(5,5) 0.5x10 5

B (10,4)

C (2.5,- 2.5)

.. m = m, . AD || BC

..(1)

Slope of AB (m,) = = -4-3.5 10-2.5 = -7.5 7.5 =-1.

A (2.5, 3.5)

B (10, 4)

Slope of CD (m) =

C (2.5, -2.5)

D(-5,5)

5-(-2.5) 7.5 =-1

= -5- 2.5 -7.5

mg = m :: AB || CD.

...(2)

From (1) and (2), the opposite sides of the quadrilateral are parallel to each other.

Mid point of AC =

2.5+2.5 3.5-2.5

2 2

= (2.5, .5)

& mid point of BD =

10-5-4+ 2

= (2.5,.5)[: mid point of AC = mid point of BD]

:: The given points form a parallelogram.

Answer 2

Step-by-step explanation:

hope it helps you madam

okay sir