show that the points o(0,0) A(3, root 3) and B(3, -root3) are the vertices of an equilateral triangle . find the area of this triangle
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Answered by
78
sorry area is
sin60=oc/√12
√3/2=oc /√12
oc=√36/2
therefore area is
=1/2 × √36/2 ×√12
= 1/2× 6/2×√12
= 1/2 ×3 × 2√3
= 3√3
sin60=oc/√12
√3/2=oc /√12
oc=√36/2
therefore area is
=1/2 × √36/2 ×√12
= 1/2× 6/2×√12
= 1/2 ×3 × 2√3
= 3√3
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you have written root 3/2 =oc/root 2
but it should come root 12
wait i correct it
cheak it now
i made it correct
BUT I LIKE YOU BECAUSE YOU ARE ANSWERING ALL MY QUESTION
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check the answer i make it correct
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Answered by
1
Two vertices of an equilateral triangle are (0,0)and(3,√3).
Let the third vertex of the equilateral triangle be (x,y)
Distance between (0,0)and(x,y) = Distance between(0,0)and(3,√3) = Distance between (x,y)and(3,√3)
(x
2
+y
2
)
=
(3
2
+3)
=
(x−3)
2
+(y−
3
)
2
x
2
+y
2
=12
x
2
+9−6x+y
2
+3−2
3y
=12
24−6x−2
3y
=12
−6x−2
3y
=−12
3x+
3y
=6
x=
3
6−
3y
3
(6−
3y
)
2+y
2
=12
9
(36+3y2−12
3y
)
+y
2
=12
36+3y
2
−12
3y
+9y2=108
−12
3y
+12y
2
−72=0
−3y
+y2−6=0
(y−2
3
)(y+
3
)=0
y=2
3
or
−3
Ify=2
3
,x=(6−6)/3=0
Ify=−
3
,x=
3
9
=3
So,the third vertex of the equilateral triangle=(0,2
3
)or(3,−
3
).
Step-by-step explanation:
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