Question

show that the polynomial f(x) = xto power4 +4xsquare + 6 has no zero.

Answer 1

$f(x) = {x}^{4} + 4x {}^{2} + 6 \\ let \: {x}^{2} = y \\ f(y) = {y}^{2} + 4y + 6 = 0 \\ discriminant = \sqrt{ {4}^{2} - 4 \times 6} \\ = - ve \\ hence \: no \: solution \: possible$
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