Question

show that the polynomial x^2 - 6x +12 has no zero

Answer 1

Heya !!!



X² - 6X + 12



A = Coefficient of X² = 1



B = Coefficient of X = -6

And,


C = Constant term = 12



Discriminant ( D ) = B²-4AC

=> (-6)² - 4 × 1 × 12



=> 36 - 48


=> -12<0


Discriminant of the given equation is smaller than 0. So the given polynomial has no zero.


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Answer 2

hey dear


here is your answer


x^2 - 6x + 12


Here as we know

a = 1 b = -6x c = 12


Now we use quadratic formula

b^2 - 4ac


b* ( 6 )^2 -4 * 1 * 12

36 -48

= - 12



Determinant of equation

- 12 is smaller than zero


and it's negative


so it has no zero

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hope it helps

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