show that the polynomial x²+2x+7 has no zeroes?
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Concept :
The discriminant (D) of a quadratic polynomial tells us about its zeroes, whether it has two distinct roots or only one root or imaginary roots.
If D > 0 ; then the quadratic polynomial has two distinct real roots
If D = 0 ; then the quadratic polynomial has one real root or two equal roots
If D < 0 ; then the quadratic polynomial has no real roots.
Solution :
Hence to check the roots of x²+2x+7 = 0 we simply need to check its Discriminant
In x²+2x+7;
a = 1 , b = 2 , c = 7
Hence D = b² - 4ac = 2² -4(1)(7) = 4 - 28 = -24
Since -24 < 0
Hence x²+2x+7 = 0 has no real roots
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