Question

Show that the polynomial x2+6x+10 has no real zeroes

Answer 1

Step-by-step explanation:

P(x) = x² + 6x + 10

a = 1 , b = 6 , c = 10

D = b² - 4ac

⇒ D = (6)² - 4(1)(10)

⇒ D = 36 - 40

⇒ D = -4

As the value of D<0 P(x) has no real roots.