show that the polynomial x2-6x+12 has no real zeroes
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Sol:
x2 - 2x + 5
when compared with the standard form of the quadratic equation, a = 1, b = - 2, c = 5
Value of the discriminant = b2 - 4 ac
= (-2)2 - 4(1) (5)
= 4 - 20
= - 15
The value of the discriminant is negative i.e less than zero.
Hence, the quadratic equation x2 - 2x + 5 has no real zeroes.
x2 - 2x + 5
when compared with the standard form of the quadratic equation, a = 1, b = - 2, c = 5
Value of the discriminant = b2 - 4 ac
= (-2)2 - 4(1) (5)
= 4 - 20
= - 15
The value of the discriminant is negative i.e less than zero.
Hence, the quadratic equation x2 - 2x + 5 has no real zeroes.
ishanpandey007:
its not 2x its x to the power two
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9
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