Show that the polynomial x4+4x2+5 has no zero
Anonymous:
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Answers
Answered by
33
Hey user !!
Here is your answer !!
_________________________________________
x^4+4x^2+5=0
By applying quadratic formula
D=b^2-4ac
D=(4)^2-4(1)(5)
D=16-20
D=-4
It has no real roots
Hope it is satisfactory :-)
____________________________________
Here is your answer !!
_________________________________________
x^4+4x^2+5=0
By applying quadratic formula
D=b^2-4ac
D=(4)^2-4(1)(5)
D=16-20
D=-4
It has no real roots
Hope it is satisfactory :-)
____________________________________
Answered by
36
⍟ Hey! ⍟
_____________________________________________________________________________________________
= x^4 + 4x² + 5
= (x²)² + 4x²+ 5
_______________________________
•Put x² = a
=> x^4 + 4x² + 6 = (x²)² + 4x² + 5
= a² + 4a + 5
•To get the zero of the polynomial
•Take a²+ 4a + 5 = 0
•So this equation has no real square root
•So there is no zero for this given polynomial
_____________________________________________________________________________________________
Regards :)
⍟ Cybary ⍟
Be Brainly :)
_____________________________________________________________________________________________
= x^4 + 4x² + 5
= (x²)² + 4x²+ 5
_______________________________
•Put x² = a
=> x^4 + 4x² + 6 = (x²)² + 4x² + 5
= a² + 4a + 5
•To get the zero of the polynomial
•Take a²+ 4a + 5 = 0
•So this equation has no real square root
•So there is no zero for this given polynomial
_____________________________________________________________________________________________
Regards :)
⍟ Cybary ⍟
Be Brainly :)
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