Math, asked by kumarshambhavi86, 1 month ago

show that the polyomial 9x^{2}+6x+4 has no real zeroes.

Answers

Answered by regatinikhitha2004
0

Step-by-step explanation:

9x²+6x+4

put a=9 b=6c=4

6²-4(9)(4)

36-144

-108 is less than 0

hence it doesn't have real values of x

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