Question

Show that the pressure exerted by an ideal gas is two third of its kinetic energy per unit volume

Answer 1

Step by step Explanation :

According to kinetic theory for gases, the pressure is given by,

P = ρv²/3

The density of a gas is given by the ratio of mass and volume

ρ = M/V

=> P = Mv²/3V.........................eqn1

The kinetic energy of a gas is given by,

KE = Mv²/2........................eqn2

Dividing eqn1 by eqn2 we get,

P/KE = (2/3V)

=> P = (2/3) x KE/V

=> Pressure = 2/3 x kinetic energy per unit volume

Hence the pressure exerted by an ideal gas is two third of its kinetic energy per unit volume

Answer 2

Explanation:

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