Show that the product of (3/2m2+2/3n2) and (2n2-3m2) is m2n2-9m4+4n2.
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0
Answer:
2m
2
−3n
2
)(3m
2
+2n
2
)
=(2m
2
)(3m
2
)−(3n
2
)(3m
2
)+(2m
2
)(2n
2
)−(3n
2
)(2n
2
)
=6m
4
−9(mn)
2
+4(mn)
2
−6n
4
=6m
4
−5(mn)
2
−6n
4
Step-by-step explanation:
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