Show that the product of 3 positive integers is always divisible by 6
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Let the positive integers be 2,3,4
then
2×3×4=24 (divisible by 6)
Again,let the positive integers be 5,2,9
then
5×2×9=90(divisible by 6)
then
2×3×4=24 (divisible by 6)
Again,let the positive integers be 5,2,9
then
5×2×9=90(divisible by 6)
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0
The statement seems incorrect...
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