Show that the product of any four consecutive integers is divisible by 24
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Prove that the product of three consecutive integers is divisible by 6; of four consecutive integers by 24. Proof. ... In the first case, n +2=3k +3=3(k + 1) is divisible by 3 and therefore so is n(n + 1)(n + 2) and in the second case n +1=3k +3=3(k + 1) is divisible by 3 and therefore so is the product n(n + 1)(n + 2)
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