Question

show that the product of any three consecutive positive integer is always divisible by 6​

Answer 1

If you take any 3 consecutive numbers, then one pf it is divisable by 2 and one of it is divisable by 3 for sure.

So, as number is divisable by 2 and 3 both, so it will be divisable by 6 as well.

Answer 2

Answer:

(3+3), (4+2), (5+1)

Step-by-step explanation:

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