show that the product of three concicutive natural numbers is divisible by 6
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Answer:
Step-by-step explanation:
Let three consecutive positive integers be, n, n + 1 and n + 2. When a number is divided by 3, the remainder obtained is either 0 or 1 or 2. ∴ n = 3p or 3p + 1 or 3p + 2, where p is some integer. If n = 3p, then n is divisible by 3.
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Take any three consecutive natural mumbers.
Multiply them and find the product.
You will observe that the product is divisible by 6.
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