Show that the product of three consecutive natural numbers is divisible by 6
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1 st no be x
2 nd no be x+1
3 rd no be x+2
x + x + 1 + x + 2 = 6
3x+3 =6
3× = 6 - 3
3x = 3
x = 3 ÷3
x = 1
1 st no be 1
2nd no be 1 + 1 = 2
3 rd no be 1 + 2 = 3
hope this helps you
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2 nd no be x+1
3 rd no be x+2
x + x + 1 + x + 2 = 6
3x+3 =6
3× = 6 - 3
3x = 3
x = 3 ÷3
x = 1
1 st no be 1
2nd no be 1 + 1 = 2
3 rd no be 1 + 2 = 3
hope this helps you
mark as brainlist
rimjhimsingh37:
Mark's as brainlist
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