Question

show that the product of two consecutive integers is divisible by 2​

Answer 1

Answer:

a*b

let take a as 6

and b as 3

6*3= 18

18/2

=9

Hence it is drvisible by 2

Hope this will help u

Answer 2

Answer:

HERE WE GO

Step-by-step explanation:

Let take the 2 consecutive numbers be, x,x+1

so AUTOMATICALLY product of these consecutive numbers, =x(x+1)

=>let, x=2k

=>product =2k[2k+1]

product =2k[2k+1]from above eq we observed that the product is divisible by 2

hat the product is divisible by 2let, x=2k+1

hat the product is divisible by 2let, x=2k+1product =(2k+1)[(2k+1)+1]

hat the product is divisible by 2let, x=2k+1product =(2k+1)[(2k+1)+1]=2(2k2+3k+1)

hat the product is divisible by 2let, x=2k+1product =(2k+1)[(2k+1)+1]=2(2k2+3k+1)from above equation it is clear that the product is divisible by 2

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