show that the product of two cosecutive numbers is divisible by 2
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Let 1st no. be even ( 2n ) so , next will be odd so, ( 2n + 1 )
Their product = (2n) * (2n+1)
= 4n² + 2n
= 2 * ( 2n² + n )
So, it is divisible by 2
Their product = (2n) * (2n+1)
= 4n² + 2n
= 2 * ( 2n² + n )
So, it is divisible by 2
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