show that the produduct of areas of the floor and two adjacent walls of a cuboid is the square of its volume.
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Dimensions of the hall :
Let length of the hall = l units
Breadth of the hall = b units
Hight of the hall = h u its
i ) Area of the floor = lb sq. umits --------( 1 )
ii ) Area of the one adjacent wall = lh sq units ----------( 2 )
iii ) Area of the second adjacent wall = bh sq units -----( 3 )
Product of three areas = ( 1 ) × ( 2 ) × ( 3)
= lb × lh × bh ( sq unit )^3
= l^2 × b ^2 × h ^2
= ( lbh ) ^2
= ( volume ) ^2 (sq units )^3
I hope this helps you.
****
Let length of the hall = l units
Breadth of the hall = b units
Hight of the hall = h u its
i ) Area of the floor = lb sq. umits --------( 1 )
ii ) Area of the one adjacent wall = lh sq units ----------( 2 )
iii ) Area of the second adjacent wall = bh sq units -----( 3 )
Product of three areas = ( 1 ) × ( 2 ) × ( 3)
= lb × lh × bh ( sq unit )^3
= l^2 × b ^2 × h ^2
= ( lbh ) ^2
= ( volume ) ^2 (sq units )^3
I hope this helps you.
****
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