Show that the progression -1,1/4,3/2,11/4..... is an AP . Find its nth term
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CONCEPT OF ARITHMETIC PROGRESSIONS , FOUR FUNDAMENTAL OPERATIONS , GENERAL TERM FORMULA .
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We can find if the common difference is same for the terms :
Here t1 = -1, t2 = 1/4, t3 = 3/2, t4 = 11/4
Common difference d = t(n+1) - tn
For n = 1
d = t2 - t1 = 1/4 - (-1) = 1/4 + 1 = 5/4
For n = 2
d = t3 - t2 = 3/2 - 1/4 = (6-1)/4 = 5/4
For n = 3
d = t4 - t3 = 11/4 - 3/2 = (11-6)/4 = 5/4
Here t2 - t1 = t3 - t2 = t4 - t3 = 5/4
Hence the common difference d is same for all the terms.
So, the given progression is in A.P. ✔✔
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