Question

show that the progression 6,11/2,5,9/2,4--------is an AP.also find it's common difference.explain?​

Answer 1

Answer:

In order to show that given series in A.P.

Common difference should be equal :

i.e. t₂ - t₁ = t₃ - t₂

For series :

6 , 11 / 2 , 5 , 9 / 2 , 4

= > t₂ - t₁ = 11 / 2 - 6

= > t₂ - t₁ = - 1 / 2

Now :

t₃ - t₂ = 5 - 11 / 2

= > t₃ - t₂ = - 1 / 2

Since common difference is same!

Therefore , given series is in A.P. with common difference d = - 1 / 2