Question

Show that the quadratic equation 2√2x^2 + √15x + √2 = 0 has no real roots by the method of completing the square

Answer 1

Answer:

Q.E.D

Step-by-step explanation:

→ 2√2x² + √15x + √2 = 0

→ 2√2x² + √15x = - √2

→ x² + √15x/(2√2) = - √2/(2√2)

→ x² + √30x/4 = - 1/2

→ x² + 2(√30/8)x + (√30/8)² = - 1/2 + (√30/8)²

→ (x + √30/8)² = 1/2 + 30/64

→ x + √30/8 = √(62/64)

→ x + √30/8 = ± √62/8

Case 1: When it's + √62/8

→ x = (√62-√30)/8

Case 2: When it's - √62/8

→ x = (- √62 - √30)/8

Hence in both cases, root's aren't real.

Hence Proved.

Answer 2

Answer:

Step-by-step explanation:

Kindly,Refer to the answer in the attachment ✔️✔️✔️

✔️In both the cases the roots are not equal .

✔️Hence we have proved !