show that the quadrilateral ABCD is a rectangle if the diagonals are equal and bisect each other.also in this quadrilateral MNO and P are the mid- points of the sides AB,BC,DA and DA respectively. show that the quadrilateral MNOP to be a rhombus
Answers
Answer:
Step-by-step explanation:
Sum of all the angles of quadrilateral = 360°
∴ 3x + 5x + 9x + 13x = 360°
⇒ 30x = 360°
∴ 3x = 3 × 12° = 36°
5x = 5 × 12°= 60°
9x = 9 × 12° = 108°
13x = 13 × 12° = 156°
⇒ The required angles of the quadrilateral are 36°, 60°, 108° and 156°.
Q2. If the diagonals of a parallelogram are equal, then show that it is a rectangle.
Sol: A parallelogram ABCD such that AC = BD In ΔABC and ΔDCB,
AC = DB
[Given]
AB = DC
[Opposite sides of a parallelogram]
BC = CB
Step-by-step explanation:
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