Question

Show that the quadrilateral formed by joining the middle points of the consecutive sides of a rectangle is a rhombus

Answer 1

Step-by-step explanation:

Refer to the attachment!!

⚡Hope it will help you.⚡

Answer 2

in ∆ADB, EG is the line segment joining the mid points of side AD and AB respectively.

therefore ,

EG is parallel to BD and half of it. -------(1)[by

mid point theorem]

similarly , FH is parallel to BD and half of it --(2)

also ,EH ||BD and EH 1/2 BD ---------(3)

GF||BD and GF1/2BD---------(4)

From eq 1 , 2 ,3,4 , we get

GE= FH=EH=GF ,

therefore, EHFG is a rhombus

hence proved.

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