Question

Show that the radius of a Bohr orbit is directly proportional to the square of the principle quantum number. Calculate the de Broglie wavelength of an electron moving with speed of 10 cm/s. [h = 6.63 x 10-34 Js mass of electron m = 9.11 X 10-31 kg]​

Answer 1

Explanation:

According to de Broglie's equation

λ=

mv

h

where, λ= de-Broglie wavelength

h=6.626×10

−34

Js=Planck's constant

m=mass of electron=9.1×10

−31

kg

velocity of electron, v=2.19×10

6

m/s

upon substitution we get:

λ=

9.1×10

−31

×2.19×10

6

6.626×10

−34

λ=0.332×10

−9

=3.32×10

−10

m