Show that the range of projection of a projectile for two angles of a projection α andβ is same where α +β = 90degree
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Hey mate ...
here's the answer ...
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Explanation:
The two angles of projection which the horizontal range is same are αα and 90−α90−α
H1=u2sin2α2gH1=u2sin2α2g
H2=u2sin2(90−α)2gH2=u2sin2(90−α)2g
=u2cos2α2g=u2cos2α2g
H1+H2=u22gH1+H2=u22g(sin2α+cos2α)(sin2α+cos2α)
=u22g
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